Displacement is at most the integral of the speed #
In this file we prove several version of the following fact:
the displacement (dist (f a) (f b)) is at most the integral of βderiv fβ over [a, b].
Displacement is at most the integral of an upper estimate on the speed.
Let f : β β E be a function which is continuous on a closed interval [a, b]
and is differentiable on the open interval (a, b).
If B t is an integrable upper estimate on βf' tβ, a < t < b,
then βf b - f aβ β€ β« t in a..b, B t.
Let f : β β E be a function which is continuous on [a, b] and is differentiable on (a, b).
Suppose that βf' tβ β€ C for a.e. t β (a, b).
Then the distance between f a and f b
is at most C times the measure of x β (a, b) such that f' x β 0.
This lemma is useful, if f is known to have zero derivative at most points of [a, b].
Consider a function f : E β F continuous on a segment [a, b]
and line differentiable in the direction b - a at all points of the open segment (a, b).
If ββ_{b - a} fβ β€ C at a.e. all points of the open segment,
then βf b - f aβ β€ C * volume s, where s is the set of points t β Ioo 0 1
such that f has nonzero line derivative in the direction b - a at lineMap a b t.
Let f : E β F be a function differentiable on a set s and continuous on its closure.
Let a, b be two points such that the open segment connecting a to b is a subset of s.
If βDfβ β€ C everywhere on s then βf b - f aβ β€ C * volume u,
where u is the set of points t β Ioo 0 1
such that f has nonzero derivative at lineMap a b t.
Let f : E β F be a function differentiable in a neighborhood of a.
If $Df(x) = O(βx - aβ ^ r)$ as x β a, where r β₯ 0,
then $f(x) - f(a) = O(βx - aβ ^ {r + 1})$ as x β a.
Let f : E β F be a function differentiable in a neighborhood of a.
If $Df(x) = O(βx - aβ ^ r)$ as x β a, where r β₯ 0, and f a = 0,
then $f(x) = O(βx - aβ ^ {r + 1})$ as x β a.