The real numbers are an Archimedean floor ring, and a conditionally complete linear order. #
A nonempty, bounded below set of real numbers has a greatest lower bound.
Equations
As โจ i, f i = 0 when the domain of the real-valued function f is empty, it suffices to show
that all values of f are at most some nonnegative number a to show that โจ i, f i โค a.
See also ciSup_le.
As โจ
i, f i = 0 when the domain of the real-valued function f is empty, it suffices to show
that all values of f are at least some nonpositive number a to show that a โค โจ
i, f i.
See also le_ciInf.
As sSup s = 0 when s is an empty set of reals, it suffices to show that all elements of s
are nonpositive to show that sSup s โค 0.
As โจ i, f i = 0 when the domain of the real-valued function f is empty,
it suffices to show that all values of f are nonpositive to show that โจ i, f i โค 0.
As sInf s = 0 when s is an empty set of reals, it suffices to show that all elements of s
are nonnegative to show that 0 โค sInf s.
As โจ
i, f i = 0 when the domain of the real-valued function f is empty,
it suffices to show that all values of f are nonnegative to show that 0 โค โจ
i, f i.
As sSup s = 0 when s is a set of reals that's unbounded above, it suffices to show that s
contains a nonnegative element to show that 0 โค sSup s.
As โจ i, f i = 0 when the real-valued function f is unbounded above,
it suffices to show that f takes a nonnegative value to show that 0 โค โจ i, f i.
As sInf s = 0 when s is a set of reals that's unbounded below, it suffices to show that s
contains a nonpositive element to show that sInf s โค 0.
As โจ
i, f i = 0 when the real-valued function f is unbounded below,
it suffices to show that f takes a nonpositive value to show that 0 โค โจ
i, f i.
As sSup s = 0 when s is a set of reals that's either empty or unbounded above,
it suffices to show that all elements of s are nonnegative to show that 0 โค sSup s.
As โจ i, f i = 0 when the domain of the real-valued function f is empty or unbounded above,
it suffices to show that all values of f are nonnegative to show that 0 โค โจ i, f i.
As sInf s = 0 when s is a set of reals that's either empty or unbounded below,
it suffices to show that all elements of s are nonpositive to show that sInf s โค 0.
As โจ
i, f i = 0 when the domain of the real-valued function f is empty or unbounded below,
it suffices to show that all values of f are nonpositive to show that 0 โค โจ
i, f i.
Exponentiation is eventually larger than linear growth.