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Mathlib.AlgebraicGeometry.Normalization

Relative Normalization #

Given a qcqs morphism f : X ⟶ Y, we define the relative normalization f.normalization, along with the maps that f factor into:

It satisfies the universal property: For any factorization X ⟶ T ⟶ Y with T ⟶ Y integral, the map X ⟶ T factors through f.normalization uniquely. The factorization map is AlgebraicGeometry.Scheme.Hom.normalizationDesc, and the uniqueness result is AlgebraicGeometry.Scheme.Hom.normalization.hom_ext.

We also show that normalization commutes with disjoint unions and smooth base change.

Given a morphism f : X ⟶ Y, this is the presheaf of integral closure of Y in X.

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    The inclusion from the structure presheaf of Y to the integral closure of Y in X.

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      The diagram of affine schemes that we glue to form the normalization.

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        Given f : X ⟶ Y, f.normalization is the relative normalization of Y in X.

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          This is the open cover of f.normalization by Spec of integral closures of Γ(Y, U) in Γ(X, f ⁻¹ U) where U ranges over all affine opens.

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            The dominant morphism into the relative normalization.

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              The morphism from the relative normalization to itself. This map is integral.

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                The sections of the relative normalization on the preimage of an affine open is isomorphic to the integral closure.

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                  noncomputable def AlgebraicGeometry.Scheme.Hom.normalizationDesc {X Y : Scheme} (f : X Y) [QuasiCompact f] [QuasiSeparated f] {T : Scheme} (f₁ : X T) (f₂ : T Y) [IsIntegralHom f₂] (H : f = CategoryTheory.CategoryStruct.comp f₁ f₂) :

                  Given an qcqs morphism f : X ⟶ Y, which factors into X ⟶ T ⟶ Y with T ⟶ Y integral, the map X ⟶ T factors through f.normalization uniquely. (See normalization.hom_ext for the uniqueness result)

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                    The uniqueness part of the universal property for relative normalization. Suppose f : X ⟶ Y is qcqs and factors into X ⟶ T ⟶ Y with T ⟶ Y affine, then there is at most one map f.normalization ⟶ T that commutes with them.

                    The normalization of Y in a coproduct is isomorphic to the coproduct of the normalizations in each of the components.

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                      The comparison lemma between the normalization of the pullback to the pullback of the normalization. This is an isomorphism when g is smooth.

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                        Normalization commutes with smooth base change.